Tuesday, February 5, 2008

do something a given number of times (bash)

Like this (do from 1 to 34) ./intensity2cycle ./s_1_0001_sig2.txt.filtered ./cycleNUMBER NUBMER

for i in $(seq 1 34); do ./intensity2cycle ./s_1_0001_sig2.txt.filtered ./cycle$i $i; done
at

3 comments:

  1. AnonymousFebruary 5, 2008 at 10:16 AM

    Alternatively use the built-in arithmetic bash looping:
    for ((i=1; i<=34; i++)); do ./intensity2cycle ./s_1_0001_sig2.txt.filtered ./cycle$i $i; done

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  2. newFebruary 6, 2008 at 10:50 AM

    cheers, that looks like a better way of doing it.

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  3. AnonymousSeptember 5, 2008 at 10:19 AM

    better yet, brace expansion ...

    for i in {1..34}
    do
    ./intensity2cycle
    ./s_1_0001_sig2.txt.filtered
    ./cycle$i $i
    done

    This gives you better performance than the previous mentions; although, at 34 iterations, you won't see much of an improvement.

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